Question

If root 3 and minus 2 root 3 are the roots of quadratic equation then form the quadratic equation

Answer 1

Answer:

${x}^{2} + \sqrt{3} x - 6 = 0$

Step-by-step explanation:

${x}^{2} - ( \sqrt{3} - 2 \sqrt{3} )x + \sqrt{3} \times ( - 2 \sqrt{3} ) = 0 \\ \\ {x}^{2} + \sqrt{3} x - 6 = 0 \\ \\ plzzz \: mark \: as \: brainliest$