Question

If root 3+root2 by root3-root2 is equal to a+b root6
Then find the value of a+b

Answer 1

here is your answer....

Answer 2

√3 + √2/√3 - √2 = a + b√6

√3 + √2 * (√3 + √2)/√3 - √2 * (√3 + √2)

= (√3 + √2)^2/(√3)^2 - (√2)^2

= (√3)^2 + 2*√3*√2 + (√2)^2/3 - 2

= 3 + 2√6 + 2/1

= 5 + 2√6

Therefore, a = 5, b = 2 and then √6

Hope it helps :)