If root 3 sin theta = cos theta, find value of. sin theta.tan theta (1+cot theta)/sin theta + cos theta
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Given:
√3 sin theta = cos theta
=>(sin theta)/(cos theta)= 1/√3
=> tan theta = tan 30°
Therefore,
theta = 30° ----(1)
Now ,
Value of sin theta.tan theta (1+cot theta)/sin theta + cos theta
= [ sin30°tan30°(1+cot30°)]/(sin30°+cos30°)
= [(1/2)(1/√3)(1+√3)]/[1/2+√3/2]
= [1/(2√3)(1+√3)]/[(1+√3)/2]
After cancellation, we get
= 1/√3
Therefore,
Required value = 1/√3
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