If root 3 sin theta = cos theta, find value of. sin theta.tan theta (1+cot theta)/sin theta + cos theta
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sin / cos=1/√3
tan = 1/√3
tan = p/b
p=1 and b=√3 ( where p is perpendicular and b is base)
so by solving u will get h=2
now put the values according to question
sin = 1/2 cos=√3/2
tan =1/√3 cot =√3/1
now u just have to solve it and u will get the answer
tan = 1/√3
tan = p/b
p=1 and b=√3 ( where p is perpendicular and b is base)
so by solving u will get h=2
now put the values according to question
sin = 1/2 cos=√3/2
tan =1/√3 cot =√3/1
now u just have to solve it and u will get the answer
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