if root 3 tan theta equals to 3 sin theta, then find the value of sin square theta-cos square theta.
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√3 tanФ = 3 sinФ
Squaring both sides
3 tan²Ф = 9 sin²Ф
3(sin²Ф/cos²Ф) = 9 sin²Ф [∵ tanФ = sinФ/cosФ]
Dividing both sides by sin²Ф
3/cos²Ф = 9
cos²Ф = 3/9
cos²Ф = 1/3 ------- ( i )
Further
1 - sin²Ф = 1/3 [ ∵ cos²Ф = 1 - sin²Ф]
sin²Ф = 1 - 1/3
sin²Ф = 2/3 --------- ( ii )
∴ sin²Ф - cos²Ф = 2/3 - 1/3 [from ( i ) and ( ii )]
= 1/3
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