Question

if root 3 x_2 is equal to 2 root 3 + 4 then the value of x is

Answer 1

$3x - 2 = 2 \sqrt{3 } + 4$

Answer 2

$\sqrt{3x - 2} = 2 \sqrt{3} + 4 \\ {( \sqrt{3x - 2)} }^{2} = {(2 \sqrt{3} + 4) }^{2} \\ 3x - 2 = 12 + 16 + 16 \sqrt{3} \\ 3x = 30 + 16 \sqrt{3} \\ x = 10 + \frac{16 \sqrt{3} }{3}$