Question

if root 5 = 2.236 and root10=3.162, find 15/root10+root20+root40-root5-root80

Answer 1

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$\frac{15}{ \sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80} } \\ = \frac{15}{ \sqrt{10} + 2 \sqrt{5} + 2 \sqrt{10} - \sqrt{5} - 4 \sqrt{5} } \\ = \frac{15}{3 \sqrt{10} - 3 \sqrt{5} } \\ = \frac{5 }{ \sqrt{10} - \sqrt{5} } = \frac{5}{3.162 - 2.236} \\ = \frac{5}{0.926} = 5.399$
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Answer 2

Answer:

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\begin{gathered} \frac{15}{ \sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80} } \\ = \frac{15}{ \sqrt{10} + 2 \sqrt{5} + 2 \sqrt{10} - \sqrt{5} - 4 \sqrt{5} } \\ = \frac{15}{3 \sqrt{10} - 3 \sqrt{5} } \\ = \frac{5 }{ \sqrt{10} - \sqrt{5} } = \frac{5}{3.162 - 2.236} \\ = \frac{5}{0.926} = 5.399\end{gathered}10+20+40−5−8015=10+25+210−5−4515=310−3515=10−55=3.162−2.2365=0.9265=5.399