if the product of zeroes of the polynomial ax²-6x-6 is 4 find the value of A
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Answered by
22
alpha ×beta=c/a
4=-6/a
4a=-6
a=-6/4
a=-3/2
4=-6/a
4a=-6
a=-6/4
a=-3/2
vijay367:
you are so kind
Answered by
21
Hey dear !!!
___________________________
==> In the question,
p(x) = ax² - 6x - 6
We have given that,
The product of zeroes of the given polynomial is 4 .
We have to find the value of a.
We also have,
a = a
b = -6
c = -6
let α and β be the zeros of the given polynomial.
Hence,
αβ = 4 ...................(given)
We know that,
α + β = -b/a
= -(-6/a)
= 6/a
we also know that,
αβ = c/a
= -6/a
but, we already have αβ = 4 hence,
4 = -6/a
-6/a = 4
-6 = 4a
-6/4 = a
a = -3/2
Therefore, the value of a is -3/2
Thanks !!
[ Be Brainly ]
___________________________
==> In the question,
p(x) = ax² - 6x - 6
We have given that,
The product of zeroes of the given polynomial is 4 .
We have to find the value of a.
We also have,
a = a
b = -6
c = -6
let α and β be the zeros of the given polynomial.
Hence,
αβ = 4 ...................(given)
We know that,
α + β = -b/a
= -(-6/a)
= 6/a
we also know that,
αβ = c/a
= -6/a
but, we already have αβ = 4 hence,
4 = -6/a
-6/a = 4
-6 = 4a
-6/4 = a
a = -3/2
Therefore, the value of a is -3/2
Thanks !!
[ Be Brainly ]
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