If root 5-root 2/root 5 +root 2 then find the value of a-b root 10
Answers
Answered by
1
Solution :
LHS = (√5-√2)/(√5+√2)
= [(√5-√2)(√5-√2)]/[(√5+√2)(√5-√2)]
= ( √5-√2 )²/[(√5)² - (√2 )²]
= ( 5 + 2 - 2•√5•√2 )/(5-2)
= (7-2√10)/3
= 7/3 - (2/3)√10
= a - b√10 ( given )
Therefore ,
a = 7/3,
b = 2/3
•••••
Answered by
0
Answer:
a=7 b=2
Step-by-step explanation:
answer is
7+2root10/4-5
there fore
a=7
B=2
7-2root10
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