If root a+root b- root c =0 find the value of (a+b-c) ^2
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√a+√b-√c =0
(a+b-c)^2=?
(√a+√b-√c)^2
(√a+b-c)^2
a+b-c=0
(a+b-c)^2=?
(√a+√b-√c)^2
(√a+b-c)^2
a+b-c=0
Answered by
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a+b-c^2=0
hope it helps you
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