if root x + Y equal to 11 and X + root Y is equal to 7 then find the value of x and y
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root x + y = 11. Equation 1
root y + x = 7. Equation 2
root y = 7 - x. Square both sides
y = x^2 -14x + 49.
root x + y = 11. Substitute for y, x^2 -14x + 49
root x + x^2 -14x + 49 -11 = 0. Re-arrange.
x^2 -14x + root x + 38 = 0
Let a = root x. Then
a^4 - 14 a^2 + a + 38 = 0
True when a = 2.
a = root x = 2
Substitute root x = 2 into equation 1 which is root x + y = 11 and get y = 9
Check out solution in equation 2.
Answer x = 4 and y = 9
root y + x = 7. Equation 2
root y = 7 - x. Square both sides
y = x^2 -14x + 49.
root x + y = 11. Substitute for y, x^2 -14x + 49
root x + x^2 -14x + 49 -11 = 0. Re-arrange.
x^2 -14x + root x + 38 = 0
Let a = root x. Then
a^4 - 14 a^2 + a + 38 = 0
True when a = 2.
a = root x = 2
Substitute root x = 2 into equation 1 which is root x + y = 11 and get y = 9
Check out solution in equation 2.
Answer x = 4 and y = 9
nksingh73:
How I find the value of a in equation a^4 -14a^2+a+38=0
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