when a ball is thrown up vertically with vwlovity v it reaches the maximum height of h if one wishes to triple the maximum height then the ball should be thrown with velocity
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your answer is with 3v
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H = v^2 / (2g)
H ∝ v^2
H1/H2 = (v1 / v2)^2
H1 / (3H1) = (v1 / v2)^2
v2 = v1√3
Ball should be thrown with a velocty of 1.732v₀
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