Question

if root3 tan theta =1,then cos squaretheta-sin square theta=​

Answer 1

Answer:

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Answer 2

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Step-by-step explanation:

$\huge\bf\red{{Given: }} \\ \sf{√3 tan θ = 1 } \\ \sf{⇒ tan θ = \frac{1}{√3} } \\ \sf{⇒ θ = tan-1 ( \frac{1}{√3} )} \\ \bf\purple{ [Taking \: tan \: inverse]} \\ \sf{⇒ θ = 30°}$

$\bf{To\: find \: value \: of  \: {sin}^{2} θ – {cos}^{2} θ, } \\ \bf{substitute \: value \: of \: θ \: \: We \: get, } \\ \tt\red {{sin}^{2} \: 30° - {cos}^{2} \: 30°}\\ \Rrightarrow{ ( \frac{1}{2} )2 – ( \sqrt{ \frac{3}2 })2} \\ {\Rrightarrow \frac{1}{4} - \frac{3}{4} } \\ \Rrightarrow {\frac{ - 2}{4} } \\ \Rrightarrow  {\frac{ - 1}{2} }$

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