Question

if roots of equation X square minus x square - 2 x square - 3 x + b square minus is equal to zero are equal prove that either 1 10 A3 + B3 + C3 = 3abc ​

Answer 1

Answer:

Step-by-step explanation:

ACCORDING TO A FORMULA:

(x)^3 +(y)^3+(z)^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

ATQ(according to the question)

X^2-x^2-2x^2-3x+b^2-=0 -----------eq(1)

110a^3+b^3+c^3=3abc

110a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

from eq 1

kindly provide the complete question.