Question

If roots of the equation x^3 -12x^2+kx- 48 = 0 are in A.P., then find k and roots of the
equation​

Answer 1

Step-by-step explanation:

11th

Maths

Complex Numbers and Quadratic Equations

Quadratic Equations

Given that kx(x - 2) + 6 = ...

MATHS

Given that kx(x−2)+6=0 has real and equal roots, the root is

MEDIUM

Share

Study later

ANSWER

Given equation is: kx(x−2)+6=0

kx

2

−2kx+6=0

Then a=k,b=−2k,c=6

Then b

2

−4ac=0

So (−2k)

2

−4k(6)=0

4k

2

−24k=0

4k(k−6)=0

k=0 and k=6

Put value of k

Then 6x

2

−12x+6=0

6x

2

−6x−6x+6=0

6x(x−1)−6(x−1)=0

∴x=1