If roots of the equation x^3 -12x^2+kx- 48 = 0 are in A.P., then find k and roots of the
equation
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11th
Maths
Complex Numbers and Quadratic Equations
Quadratic Equations
Given that kx(x - 2) + 6 = ...
MATHS
Given that kx(x−2)+6=0 has real and equal roots, the root is
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ANSWER
Given equation is: kx(x−2)+6=0
kx
2
−2kx+6=0
Then a=k,b=−2k,c=6
Then b
2
−4ac=0
So (−2k)
2
−4k(6)=0
4k
2
−24k=0
4k(k−6)=0
k=0 and k=6
Put value of k
Then 6x
2
−12x+6=0
6x
2
−6x−6x+6=0
6x(x−1)−6(x−1)=0
∴x=1
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