If rs 40000 amounts to rs48620.25 in two years,compound interest payable half yearly find the rate of interest per annum
Answers
Answer:
Step-by-step explanation:
P x (1 + r/200)^4 = A
40000 × ((200+r)/200)^4 = 48620.25
((200+r)/200)^4 = 48620.25/40000=1.21550625
(200+r)/200)=1.21550625^(¼)= 1.05
200 + r = 1.05 ×200= 210.
r = 10.
Given :-
- Principal = Rs.40000
- Amount = Rs.48620.25
- Time = 2 years.
- Rate = compounded half yearly .
To Find :-
- The rate of interest per annum. ?
Solution :-
we know that, when interest is compounded half yearly ,
- Rate becomes half .
- Time becomes double.
so,
- Time = 2 * 2 = 4 years.
- Rate = Let half yearly is R% .
then,
→ P[1 + (R/100)]^T = A
→ 40000[1 + (R/100)]⁴ = 48620.25
→ [1 + (R/100)]⁴ = 48620.25/40000
→ [1 + (R/100)]⁴ = (194481/160000)
→ [1 + (R/100)]⁴ = (21/20)⁴
→ 1 + (R/100) = (21/20)
→ (R/100) = (21/20) - 1
→ (R/100) = (21 - 20)/20
→ (R/100) = (1/20)
→ R = 5% .
therefore,
→ The rate of interest per annum = 5 * 2 = 10% (Ans.)
Learn more :-
CI in 2yr is Rs. 1600 and in 3 yrs it will be Rs. 1700. Find the rate of interest.
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