Math, asked by rizzubaig370, 1 year ago

If rs 40000 amounts to rs48620.25 in two years,compound interest payable half yearly find the rate of interest per annum

Answers

Answered by gungunsharma113
22

Answer:

Step-by-step explanation:

P x (1 + r/200)^4 = A

40000 × ((200+r)/200)^4 = 48620.25

((200+r)/200)^4 = 48620.25/40000=1.21550625

(200+r)/200)=1.21550625^(¼)= 1.05

200 + r = 1.05 ×200= 210.

r = 10.

Answered by RvChaudharY50
5

Given :-

  • Principal = Rs.40000
  • Amount = Rs.48620.25
  • Time = 2 years.
  • Rate = compounded half yearly .

To Find :-

  • The rate of interest per annum. ?

Solution :-

we know that, when interest is compounded half yearly ,

  • Rate becomes half .
  • Time becomes double.

so,

  • Time = 2 * 2 = 4 years.
  • Rate = Let half yearly is R% .

then,

→ P[1 + (R/100)]^T = A

→ 40000[1 + (R/100)]⁴ = 48620.25

→ [1 + (R/100)]⁴ = 48620.25/40000

→ [1 + (R/100)]⁴ = (194481/160000)

→ [1 + (R/100)]⁴ = (21/20)⁴

→ 1 + (R/100) = (21/20)

→ (R/100) = (21/20) - 1

→ (R/100) = (21 - 20)/20

→ (R/100) = (1/20)

→ R = 5% .

therefore,

→ The rate of interest per annum = 5 * 2 = 10% (Ans.)

Learn more :-

CI in 2yr is Rs. 1600 and in 3 yrs it will be Rs. 1700. Find the rate of interest.

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