Question

if rupees 4000 amount to 5290 in 2 years ,find the rate of compund interst​

Answer 1

$\bf{\huge{\boxed{\tt{\pink{ANSWER\::}}}}}$

$\bf{Given}\begin{cases}\sf{Amount,[A]\:=\:Rs.5290}\\\\ \sf{Principal,[P]\:=\:Rs.4000}\\ \\\sf{Time,[n]\:=\:2\:years}\end{cases}}$

$\bf{\Large{\underline{\bf{To\:\:find\::}}}}$

The rate of compound Interest.

$\bf{\Large{\underline{\tt{\red{Explanation\::}}}}}$

We know that formula of the compound Interest = Amount - Principal

Or

$\leadsto\sf{\green{A\:=\:P(1+\frac{R}{100} )^{n} }}$

So,

$\longmapsto\sf{5290\:=\:4000(1+\frac{R}{100})^{2} }$

$\longmapsto\sf{\frac{529\cancel{0}}{400\cancel{0}} \:=\:(1+\frac{R}{100} )^{2} }$

$\longmapsto\sf{\frac{529}{400} \:=\:(1+\frac{R}{100} )^{2} }$

$\longmapsto\sf{\sqrt{\frac{529}{400} } \:=\:(1+\frac{R}{100})}$

$\longmapsto\sf{\frac{23}{20} \:=\:(1+\frac{R}{100} )}$

$\longmapsto\sf{\frac{23}{20} -1\:=\:\frac{R}{100} }$

$\longmapsto\sf{\frac{23\:-\:20}{20} \:=\:\frac{R}{100} }$

$\longmapsto\sf{\frac{3}{20} \:=\:\frac{R}{100} }$

$\longmapsto\sf{20R\:=\:300}$

$\longmapsto\sf{R\:\:=\;\:\cancel{\frac{300}{20} }}$

$\longmapsto\sf{\red{R\:=\:15\%}}$

Thus,

$\bf{\Large{\boxed{\rm{The\:rate\:of\:compound\:Interest\:is\:\:15\%}}}}}$

Answer 2

Answer:

I don't no .............