Question

If (s-a) =5cm
(s-b) =10cm
(s-a) =1cm. Find a, b, c
Where a, b, c are side of the triangle.

Answer 1

Answer:

Step-by-step explanation:

(s-a) + ( s-b) + ( s-c) =5+10+1

3s-(a+b+c)=16

Note :s =semi perimeter (a+b+c )/2

5+10+1)/2=8

24-16 = a+b+c=8

Answer 2

Answer: The answer is 11 cm, 6 cm and 15 cm.

Step-by-step explanation:  We are given to find the values of a, b and c, where these three represents the sides of a triangle.

We know that if a, b and c are the three sides of a triangle, then 's' is defined by

$s=\dfrac{a+b+c}{2}.$

From the given information, we have

$s-a=5\\\\\Rightarrow \dfrac{a+b+c}{2}-a=5\\\\\Rightarrow b+c-a=10~~~~~~~~~~~~~~~~(A)$

Similarly, we find that

$c+a-b=20~~~~~~~~~~~~~~~~(B)\\\\a+b-c=2.~~~~~~~~~~~~~~~~~(C)$

Adding equations (A) and (B), we have

$2c=30\\\\\Rightarrow c=15.$

Adding equations (B) and (C), we have

$2a=22\\\\\Rightarrow a=11.$

From equation (A), we get

$b+15-11=10\\\\\Rightarrow b=6.$

Thus, a = 11 cm, b = 6 cm and c = 15 cm.