If s&T are non singular &ST=I then T –1 s-1=?
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Since, A is non-singular
So, A−1 exists.
Given, (A−2I)(A−4I)=0
⇒A2−6A+8I=0
Multiplying by A−1, we get
⇒A−6I+8A−1=0
⇒A+8A−1=6I
⇒61A+34A−1=I
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