Question

If s and S are respectively solubility and solubility product of a sparingly soluble binary electrolyte then :
(a) s = S
(b) s = S²
(c) s = $S^{1/2}$
(d) s = $\frac{1}{2}$S

Answer 1

C is the answer

because in binary electrolytes solubility product is equal to the square root of solubility