Question

Solubility product of BaCl₂ is 4 × 10⁻⁹ moles/litre. Its solubility would be :
(a) 1 × 10⁻²⁷
(b) 1 × 10⁻³
(c) 1 × 10⁻⁷
(d) 1 × 10⁻²

Answer 1

1×10^-3

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