Question

if ∆S total= -40 kJ mol x K-1
∆H system= 2000 kJ mol-
T = 400K then
Calculate value of ∆S system
(1 )- 35 kJ mol x K
(2) - 5 kJ mol x K
(3) - 40 kJ mol x K
(4) + 5 kJ mol x K​

Answer 1

Answer:

increasing. This reaction appears to violate this law because the entropy in 2 moles of ... m = 2000 mL∙1 g/mL = 2000 g ... w = -Δngas∙R ∙T = -4 mol∙8.314 J/(K∙mol)∙298 K = -9.9 kJ. 7