Question

If sec = 13/12, find sin and cot ​

Answer 1

Answer:

sin A = 5/13 and cot A = 12/5

Step-by-step explanation

Given, sec A = 13/12.

We know that , sec A = 1/cosA

                   So, cos A = 12/13

Applying sin²A+cos²A = 1 relation,

we get, sin²A = 1 - (12/13)²

            sin² A = 169-144/169

  So,      sin A = 5/13

We know that, cot A = cos A/sin A

                        cot A = 12/13 ÷ 5/13

So,        cot A = 12/5