.if sec 15θ = cosec 15θ (0° < θ < 10°) then value of θ is
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sec15@=cosec(90-15@)
sec15@=sec(90-15@)
15@=90-15@
15@+15@=90
30@=90
@=90/30
@=3 Ans
sec15@=sec(90-15@)
15@=90-15@
15@+15@=90
30@=90
@=90/30
@=3 Ans
Answered by
0
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