If sec^2Ѳ (1+sinѲ) (1-sinѲ) = k, find the value of k
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The value of k = 1
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Sec^2theta (1+Sin theta)(1-Sintheta) = k.
We need to find the value of 'k'.
Sec^2theta { 1^2 - (Sin theta)^2 } = k.
{ From (a-b)(a-b) = a^2 - b^2 }.
Sec^2 theta { 1 - Sin^2 theta} = k.
Sec^2theta { Cos^2 theta } = k.
{ 1 - Sin^2 theta = Cis^2 theta }.
Now, we know that Sec^2 theta = 1/ Cos ^2 theta.
So,
1/Cos^2 theta × Cos^2 theta = k
1 = k .
Therefore k = 1.
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