Math, asked by ishaagrawal8482, 8 months ago

If sec^2Ѳ (1+sinѲ) (1-sinѲ) = k, find the value of k

Answers

Answered by souravsarkar045
0

Answer:

The value of k = 1

I hope it helps you.

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Answered by AnnuMishra11
1

Sec^2theta (1+Sin theta)(1-Sintheta) = k.

We need to find the value of 'k'.

Sec^2theta { 1^2 - (Sin theta)^2 } = k.

{ From (a-b)(a-b) = a^2 - b^2 }.

Sec^2 theta { 1 - Sin^2 theta} = k.

Sec^2theta { Cos^2 theta } = k.

{ 1 - Sin^2 theta = Cis^2 theta }.

Now, we know that Sec^2 theta = 1/ Cos ^2 theta.

So,

1/Cos^2 theta × Cos^2 theta = k

1 = k .

Therefore k = 1.

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