if sec 2 beta = cosec ( beta - 24 degree ) and 2 beta is an acute angle , find the value of beta ?
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sec2beta=cosec(beta-24)
2 beta<90
sec(2 beta) =sec(90-beta+24)
2 beta=114-beta
3 beta =114
beta=38
Hope it helps
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2 beta<90
sec(2 beta) =sec(90-beta+24)
2 beta=114-beta
3 beta =114
beta=38
Hope it helps
If yes please mark brainliest
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1
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