Question

if sec 2a = cosec (a-18), whereb2a is an acute angle, then the value of a is

Answer 1

Answer:

36°

Step-by-step explanation:

sec 2a = cosec (a-18)

sec 2a = sec [90-(a-18)]  [ cosec θ = sec (90-θ)

2a = 90 - (a-18)

2a+a = 90+18

3a = 108.

a = 36°.

hope this helps you.......................