if sec 4A =cosec ( A-20°) then find the value of A
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Answered by
9
GIVEN
SEC 4A = COSEC (A-20)
SEC 4A = SEC [90-(A-20)]
4A=90-A+20
4A+A = 90+20
5A = 110
A = 22
SEC 4A = COSEC (A-20)
SEC 4A = SEC [90-(A-20)]
4A=90-A+20
4A+A = 90+20
5A = 110
A = 22
Answered by
2
we know that cosec (90 - Q) = secQ
therefore sec 4a = sec (90 - (a-20) )
so sec 4a = sec(90-a+20)
now we divide whole eq.. by sec we have
4a = 90 -a+20
5a = 110
a = 22..
hope it will helps you
therefore sec 4a = sec (90 - (a-20) )
so sec 4a = sec(90-a+20)
now we divide whole eq.. by sec we have
4a = 90 -a+20
5a = 110
a = 22..
hope it will helps you
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