if sec 5A=cosec(A-36),where 5A is an acute angle, find the value of A
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Answered by
153
Sec5A = cosec(A - 36)
------------
We know,
Cosec(90 - ∅) = sec∅
--------------
Then,
Sec5A = cosec(A - 36)
Cosec(90 - 5A) = cosec(A - 36)
90 - 5A = A - 36
90 + 36 = A + 5A
126 = 6A
126/6 = A
21 = A
==================
Value of A = 21°
I hope this will help you
(-:
------------
We know,
Cosec(90 - ∅) = sec∅
--------------
Then,
Sec5A = cosec(A - 36)
Cosec(90 - 5A) = cosec(A - 36)
90 - 5A = A - 36
90 + 36 = A + 5A
126 = 6A
126/6 = A
21 = A
==================
Value of A = 21°
I hope this will help you
(-:
abhi569:
(-:
Answered by
24
Answer:=21 degree
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