if sec 5a=cosec (a+36°)and 5a is a positive acute angle;let you find the value of a thita
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sec (5a) = cosec (a+36)
Now,
sec (theta) = cosec (90-theta)
So,
cosec (90-5a) = cosec (a+36)
90-5a = a+36
6a = 54°
Therefore,
a = 9°
Hope this helps you !!
Now,
sec (theta) = cosec (90-theta)
So,
cosec (90-5a) = cosec (a+36)
90-5a = a+36
6a = 54°
Therefore,
a = 9°
Hope this helps you !!
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