if sec 6A =cosec (A+6).Where 6A is an acute angle find the value
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Answered by
19
sec 6A = cosec ( A +6 )
cosec ( 90 - 6A ) = cosec ( A + 6)
90-6A = A+6
7A = 84
A = 12
cosec ( 90 - 6A ) = cosec ( A + 6)
90-6A = A+6
7A = 84
A = 12
Answered by
10
cosec ( 90 - 6A ) = cosec (A + 6 )
90 - 6A = A + 6
-6A - A = 6 - 90
-7A = - 84
A = 12
90 - 6A = A + 6
-6A - A = 6 - 90
-7A = - 84
A = 12
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