Question

if sec A = 5/4 verify that tanA/1+tan^2A= sinA/cosa​

Answer 1

Step-by-step explanation:

It can't be verified .

I will show you how.....

Given that

sec A = 5/4

we know that,

sec A = hypotenuse/ base = 5/4

So,

perpendicular= √h^2-b^2

= √5^2-4^2

= √25-16

= √9

= 3

Now ,

sin A = p/h = 3/5

tanA = p/b = 3/4

cos A = b/h= 4/5

We have to verify that,

tan A/ 1+ tan^2A = sinA/cosA

(3/4)/1+(3/4)^2 = (3/5)/(4/5)

3/4 ÷1 + 9/16 = 3/5 × 5/4

3/4÷(16 +9)/16 = 15/20

3/4 ÷ 25/16 = 3/4

3/4×16/25 =3/4

12/25=3/4

If the question is tan A / 1+ tan ^2A = sinA/ secA then it can be verified .

Hope you understand this....