Question

If sec A =5/4find the value of sin²A +cos²A​

Answer 1

Step-by-step explanation:

sec A =5/4

sec =H/B

H=5,B=4

using pythagorus theorem we get

P=3

now,we want sin^2A+cos ^2A

sin A=P/H

=3/5

cos A=B/H

=4/5

sin^2A+cos^2A

= (3/5)^2+(4/5)^2

=9/25+16/25

25/25

=1

or there is one more very simple way

you can just say it is because of identity no1 sin^2theta +cos ^2theta =1

hope you like it

mark as brainliest