If sec ( A+B ) =2 and tan ( A-B ) = 1/√3 find the value of A and B
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it is very easy follow
sec(A+B) =sec 60
A+B=60 ........i
Tan (A-B) =tan 30
A-B=30
A=30+B ......... ii
substitute in eq i
30+2B=60
2B=30
B=15
substitute in eq 2
A=30+15
=45*
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