If sec A= cosec A , then show that 2sin²A=1
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sec A = Cosec A
=> 1/ Cos A = 1/ Sin A
=> Cos A = Sin A
we know
Cos² A + Sin ² A = 1
Sin² A + Sin² A = 1
hence the answer
=> 1/ Cos A = 1/ Sin A
=> Cos A = Sin A
we know
Cos² A + Sin ² A = 1
Sin² A + Sin² A = 1
hence the answer
Answered by
0
sec A = Cosec A
⇒ 1/ Cos A = 1/ Sin A
⇒ Cos A = Sin A
we know
Cos² A + Sin ² A = 1
Sin² A + Sin² A = 1
SO 2sin²A=1 proved
⇒ 1/ Cos A = 1/ Sin A
⇒ Cos A = Sin A
we know
Cos² A + Sin ² A = 1
Sin² A + Sin² A = 1
SO 2sin²A=1 proved
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