If secA+tan A=x and secA-tan A=y , then show that xy=1
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Multiply both
LHS u will get identity and RHS u will get xy
Finally ur answer
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Sec A + Tan A = x
Sec A - Tan A = y
multiply the above LHS :
(sec A + Tan A) (Sec A - Tan A) = x y
Sec² A - Tan² A = x y
1 = xy
Sec A - Tan A = y
multiply the above LHS :
(sec A + Tan A) (Sec A - Tan A) = x y
Sec² A - Tan² A = x y
1 = xy
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