Show that cotA+tan A=secAcosecA
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Answered by
4
cotA + tanA
= cosA/sinA + sinA/cosA
= (sin²A + cos²A)/sinAcosA
= 1/sinAcosA
= secAcosecA
= cosA/sinA + sinA/cosA
= (sin²A + cos²A)/sinAcosA
= 1/sinAcosA
= secAcosecA
Answered by
2
cotA + tanA
= cosA/sinA + sinA/cosA
= (sin²A + cos²A)/sinAcosA
= 1/sinAcosA
= secAcosecA=R.H.S PROVED
= cosA/sinA + sinA/cosA
= (sin²A + cos²A)/sinAcosA
= 1/sinAcosA
= secAcosecA=R.H.S PROVED
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