Question

If sec A . sin(36+A) =1, find the value of A so that A and (36+A) are acute angles

Answer 1

Solution :

secA . sin( 36 + A ) = 1

=> sin( 36 + A ) = 1/secA

=> sin( 36 + A ) = cosA

=> sin( 36 + A ) = sin( 90 - A )

=> 36 + A = 90 - A

=> A + A = 90 - 36

=> 2A = 54

=> A = 54/2

=> A = 27°

••••

Answer 2

ĀNSWĒR ⬆⬆⬆⬆

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