Question

length a rectangle is 10 centimeter and width 8 centimeters if it's length and width are doubled what would be their the new rectangle. how many times the area of the original rectangle is the area of the new rectangle

Answer 1

Answer:

Step-by-step explanation:

Answer 2

the area of the rectangle is
$10 \times 8 = 80$
in case length and width are doubled
new length and width will be 20 and 16 cm. then the area will be
20*16=320
in case area increase is
$\frac{320}{80} = 4$
so that will be 4times