Question

If Sec A + Tan A =3 Find Sin A + CosA​

Answer 1

Answer:

sec A + Tan A =3

=>(1+sin A)=3cos A

=>(1+sin A)²=9(1-sin²A)

=>10 sin²A+2sinA-8=0

=>5 sin²A+sinA-4=0

=>5sin²A+5sinA-4sinA-4=0

=>5 sinA(sinA+1)-4(sinA+1)=0

=>(sinA+1)(5sinA-4)=0

there fore sinA=-1 & cosA=0. since cosA=√(1-sin²A)

so,sinA+cosA=-1

and,

if sinA=4/5

then cosA=3/5

so,sinA+cosA=7/5.///