Math, asked by rautayush54, 10 months ago

If sec A+tan A = 3 then sec A =
(a) (b)4/3 (0)5/3 (d) 10/3​

Answers

Answered by tejaswisubrahmanyam
1

Answer:

sec²A-tan²A=1

(secA-tanA)(secA+tanA)=1

secA-tanA = 1/3

secA+tanA=3

----------------------(Adding)

2secA = 3+1/3 = 10/3

secA = 5/3

Step-by-step explanation:

Answered by Anonymous
0

Answer:

Hope this helps you.

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