If sec A+tan A = 3 then sec A =
(a) (b)4/3 (0)5/3 (d) 10/3
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sec²A-tan²A=1
(secA-tanA)(secA+tanA)=1
secA-tanA = 1/3
secA+tanA=3
----------------------(Adding)
2secA = 3+1/3 = 10/3
secA = 5/3
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Hope this helps you.
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