If sec A+ tan A =4, then sin A equals
(b) 15/17
(c) - 8/15
(A)8/15
(d) 8/17
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find the attachment for the reqd ans mate....
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Answer:
secA + tana=4......... (1)
multiple by secA-tanA both side
sec²A-tan²A=4(secA-tanA)
1/4=secA-tanA.........(.2)
add eqn 1and eqn 2
2secA=4+1/4=17/4
secA=17/8
cosA=8/17
sinA=√(1-cos²A)
sinA=√(1-64/289) =√225/289=15/17
sinA=15/17
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