Question

two cubical dice whose face are numbered 1 to 6 are rolled simultaneously once the probability of getting sum of numbers on its face is 10​

Answer 1

Answer:3/36

Step-by-step explanation:

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Answer 2

The probability of getting sum of number on its face is 10=$\frac{1}{12}$

Step-by-step explanation:

When two dice are throws

Sample space=S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of number on its face is 10

(5,5),(6,4),(4,6)=3

Total result in one dice=6

Total cases in two dice =$6^2=36$

Favorable cases=3

The probability of getting sum of number on its face is 10=$\frac{3}{36}=\frac{1}{12}$

The probability of getting sum of number on its face is 10=$\frac{1}{12}$

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