If sec a - tan a is equals to X then show that X square + 1 upon x square - 1 is equals to minus cosec a
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Step-by-step explanation:
nθ+secθ=x,then prove that sinθ=x2−1x2+1
Given
tanθ+secθ=x.....[1]
⇒1secθ+tanθ=1x
⇒secθ−tanθsec2θ−tan2θ=1x
⇒secθ−tanθ=1x....[2]
Adding [1] and [2] we get
2secθ=x+1x....[3]
Subtracting [2] from [1] we get
2tanθ=x−1x....[4]
Dividing [4] by [3] we get
tanθsecθ=x−1xx+1x
⇒sinθ=x2−1x2+1
sumanlata121167:
No, it's not correct. First look what we have to prove only then answer.
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thanks for asking the answer is in the picture
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