if sec A+ tan A=x and sec A-tan A=y , show that xy=1
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x = sec A + tan A
y = sec A - tan A
xy = (sec A + tan A)(sec A - tan A)
⇒ xy = sec² A - tan² A = 1
⇒ xy = 1
y = sec A - tan A
xy = (sec A + tan A)(sec A - tan A)
⇒ xy = sec² A - tan² A = 1
⇒ xy = 1
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