If :
sec A + tan A = x
Show that :
sin A = (x^2 -1) / (x^ + 1)
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sec^2 A - tan^2 A = 1
( secA + tan A) ( sec A - tan A ) = 1
x (sec A - tan A ) = 1
secA- tan A = 1/ x continued in the attachment
( secA + tan A) ( sec A - tan A ) = 1
x (sec A - tan A ) = 1
secA- tan A = 1/ x continued in the attachment
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