if sec a + tan a = x then tan a = ?
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Answer:
= (x2 - 1) /2x
Step-by-step explanation:
Given, sec A + tan A = x ... (1)
Now, we know the identity 1 + tan2A = sec2A
sec2A - tan2A = 1
(secA - tanA) (sec A + tanA) = 1 [Using the identity: a2 - b2 = (a - b)(a + b)]
secA - tanA = 1/x ... (2) [Using the given equation (1)]
Now, subtract (2) from (1), we get,
2 tan A = x - 1/x = (x2 - 1) /x
Thus, tan A = (x2 - 1) /2x
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TANa=x-seca=x-1/cosa
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