If sec A+ tanA =5, find the quadrant in which A lies and find the value of sinA.
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Answer:
SinA=12/13
Step-by-step explanation:
wkt Sec²A - Tan²A = 1
⇒(SecA + TanA)(SecA - TanA)=1
given SecA+Tan A = 5 --- eq 1
⇒ SecA - TanA = 1/5 ---- eq 2
Solving Eq 1 and Eq 2,
we get SecA=13/5
⇒Cos a =5/13
By substituting Cosa in the formula Sin²A = 1-Cos²A
we get SinA = 12/13
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