Question

if sec A= under root 2 find the value of tan A​

Answer 1

Answer:

1

Step-by-step explanation:

secA = √2

We know that 1+ tan²A = sec²A

1+ tan²A = (√2)²

tan²A = 2-1

tanA = √1

tan A = 1

Answer 2

Step-by-step explanation:

Given

$\sec( \theta) = \frac{ \sqrt{2} }{1} = \frac{h}{b}$

h= root 2

b=1

p=?

By pytagoras theorem

${h}^{2} = {p}^{2} + {b}^{2}$

${ \sqrt{2} \: }^{2} = {p}^{2} + {1}^{2}$

$2 = {p}^{2} + 1$

${p}^{2} = 2 - 1$

${p}^{2} = 1$

$p = \sqrt{1}$

p =1

$\tan(a) = \frac{p}{b} = \frac{1}{1} = 1 \: ans$

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