If sec+tan=1 then find the value of sin in terms of 1
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secA +tanA = 1
1/cosA + sinA/cosA = !
[1+sinA] /cosA = 1
1+ sinA = =cos A
sinA = cos A-1
1/cosA + sinA/cosA = !
[1+sinA] /cosA = 1
1+ sinA = =cos A
sinA = cos A-1
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